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frame time after formal start: angle (degrees)
800 t= -3.637: b01= 0.000
900 t= -0.300: b01= 0.681
910 t= 0.033: b01= 1.080
920 t= 0.367: b01= 1.738
930 t= 0.701: b01= 2.939
940 t= 1.034: b01= 5.308
950 t= 1.368: b01= 5.948
960 t= 1.702: b01= 7.464
970 t= 2.035: b01= 8.088
980 t= 2.369: b01= 8.545
985 t= 2.536: b01= 9.067
990 t= 2.703: b01= 10.173
995 t= 2.870: b01= 9.106Just had another look at it, the big whack really comes a second after that, around 1020. Before that, drift.
What I find is that the angular velocity is about half the free rotation rate. This shows, as we also observe for the vertical drop motion, there was considerable (relatively constant!) resistance to the rotational motion, at least for the first few seconds of motion.
I calculate floor 85 or lower. Floors 79--83 were type 9, all above, except floor 92 were type 1; floor 92 was type 2.Major_Tom wrote:at about what floor level or elevation would the collision take place?
OneWhiteEye wrote:Dr. G, that's fascinating. An effective constant torque?
Very nice! I'll use this formula to fit (and smooth) my data. I just want a decent estimate of the tilt to apply a sin(theta) correction to all of OneWhiteEye's pixel measurements.Dr. G wrote: d(theta)/dt = Sqrt{ 3wg.sin(theta) / (h^2 + w^2) }
...
What I find is that the angular velocity is about half the free rotation rate. ...

David B. Benson wrote:femr2 --- As long as something can be learned from the tilt.
Watching your clip, I'll opine that the antenna mast is indeed loose at the base towards the end and beginning to fall off the rest of the structure.
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